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Add hacky, initial arm64 support #302
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Why were these lines changed ? Can you help me understand what
read -t 60 < /proc/self/fd/1 > /dev/null 2>&1does ?Uh oh!
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When available RAM is low, the shell fails to run processes (
fork()fails) and the shell decides to exit.dateandsleepare new processes, so sometimes CI fails because the shell can't run them. By usingechoandread(from a file descriptor there's nothing to read from, thestdoutpipe - that's/proc/self/fd/1) with timeout, two shell built-in commands (as opposed to separate executables executed by the shell), we can reliably output something every once in a while under low-memory conditions.Because the sub-shell that runs
readshares the samestdoutpipe as the parent shell, we want to redirect the output ofreadto/dev/null, otherwise, something like pressing ENTER when running interactively, can cause an infinite loop (read fromstdout, then output tostdout, repeatedly).This makes CI more reliable and makes minification very unlikely to cause the shell to terminate.