There are different ways through which we can sort a Dictionary in Python. There are many ways, depending on whether you want to sort it by key or by value.<\/p>\n\n\n\n
Let’s take a look at some of them in the article!<\/p>\n\n\n\n
If we want to sort a Dictionary in Python by value, there are a few ways using which we can achieve this.<\/p>\n\n\n\n
On newer versions on Python (Python 3.6<\/strong> and above), we can use a lambda on the We will sort the Output<\/strong><\/p>\n\n\n Indeed, we can see that our new dictionary has been sorted based on the value!<\/p>\n\n\n\n The reason why this method works on Python 3.6+ is that Dictionaries in the new versions of Python are now an ordered datatype.<\/p>\n\n\n\n This means that we can enumerate a dictionary as a list of items, and also perform operations that can change the order, such as sorting it.<\/p>\n\n\n\n But fear not. If you have an older version of Python, keep reading. We’ll show you another way to deal with this!<\/p>\n\n\n\n We can still use The below snippet will sort our dictionary by value:<\/p>\n\n\n More specifically, we form a sorted list using This will construct a callable that will grab that first element from the items list. We do this at every iteration, thereby getting a sorted dictionary!<\/p>\n\n\n\n Now, if you want to sort a Dictionary by Key, we can use the Output<\/strong><\/p>\n\n\n Indeed, the dictionary has been sorted based on the Key now!<\/p>\n\n\n\n We can again use the Again, this is the same as before, but we’ll be now sorting based on value.<\/p>\n\n\n Output<\/strong><\/p>\n\n\n Again, the output is the same as before.<\/p>\n\n\n\n In this article, we learned how we could sort a Dictionary in Python; both by key and by value, using different approaches.<\/p>\n\n\n\nsorted()<\/code> method to sort a dictionary in Python.<\/p>\n\n\n\ndict.items()<\/code>, using the key as a lambda.<\/p>\n\n\n\nmy_dict = {1: 2, 2: 10, "Hello": 1234}\n\nprint({key: value for key, value in sorted(my_dict.items(), key=lambda item: item[1])})\n<\/pre><\/div>\n\n\n\n{1: 2, 2: 10, 'Hello': 1234}\n<\/pre><\/div>\n\n\nMethod 2: Using sorted() on older versions of Python<\/h3>\n\n\n\n
sorted()<\/code> to sort the dictionary. But we something to make the Dictionary into an ordered type. The operator<\/code> module has that, using operator.itemgetter(idx)<\/code>.<\/p>\n\n\n\n\nimport operator\n\nmy_dict = {1: 2, 2: 10, "Hello": 1234}\n\nsorted_dict = sorted(my_dict.items(), key=operator.itemgetter(1))\n\nprint(sorted_dict)\n<\/pre><\/div>\n\n\nsorted(dict.items()<\/code>), and pass operator.itemgetter(1)<\/code> to it (Since the value is at index 1).<\/p>\n\n\n\n
\n\n\n\nSort a Dictionary in Python by Key<\/h2>\n\n\n\n
Method 1: Use operator.itemgetter() (Recommended method for older versions of Python)<\/h3>\n\n\n\n
operator<\/code> method, like in the last section. The only change that we have to make is to sort the list based on keys now, so we call operator.itemgetter(0)<\/code>.<\/p>\n\n\n\nimport operator\n\nmy_dict = {2: 10, 1: 2, -3: 1234}\n\n# Sort the Dict based on keys\nsorted_dict = dict(sorted(my_dict.items(), key=operator.itemgetter(0)))\n\nprint(sorted_dict)\n<\/pre><\/div>\n\n\n\n{-3: 1234, 1: 2, 2: 10}\n<\/pre><\/div>\n\n\nMethod 2: Use sorted() with a lambda (Recommended method for Python 3.6+)<\/h3>\n\n\n\n
sorted()<\/code> method, with a lambda, on newer versions of Python.<\/p>\n\n\n\n\nmy_dict = {2: 10, 1: 2, -3: 1234}\nsorted_dict = dict(sorted(my_dict.items(), key=lambda item: item[0]))\n<\/pre><\/div>\n\n\n\n{-3: 1234, 1: 2, 2: 10}\n<\/pre><\/div>\n\n\n
\n\n\n\nConclusion<\/h2>\n\n\n\n
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