Python Program to Read a Number n and Print the Series “1+2+…..+n= “

This is a Python Program to read a number n and print and compute the series “1+2+…+n=”.

The program takes a number n and prints and computes the series “1+2+…+n=”.

1. Take a value from the user and store it in a variable n.
2. Use a for loop where the value of i ranges between the values of 1 and n.
3. Print the value of i and ‘+’ operator while appending the value of i to a list.
4. Then find the sum of elements in the list.
5. Print ‘=’ followed by the total sum.
6. Exit.

Here is the source code of the Python Program to read a number n and print and compute the series “1+2+…+n=”. The program output is also shown below.

n=int(input("Enter a number: "))
a=[]
for i in range(1,n+1):
    print(i,sep=" ",end=" ")
    if(i<n):
        print("+",sep=" ",end=" ")
    a.append(i)
print("=",sum(a))
 
print()

1. User must first enter the value and store it in a variable n.
2. The for loop enables i to range between 1 and n (as n+1 is not included).
3. For each iteration, the value of i is printed.
4. ‘+’ operator is printed only if i

 
Case 1:
Enter a number: 4
1 + 2 + 3 + 4 = 10
 
Case 2:
Enter a number: 5
1 + 2 + 3 + 4 + 5 = 15

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