Skip to main content

Questions tagged [set-theory]

forcing, large cardinals, descriptive set theory, infinite combinatorics, cardinal characteristics, forcing axioms, ultrapowers, measures, reflection, pcf theory, models of set theory, axioms of set theory, independence, axiom of choice, continuum hypothesis, determinacy, Borel equivalence relations, Boolean-valued models, embeddings, orders, relations, transfinite recursion, set theory as a foundation of mathematics, the philosophy of set theory.

Filter by
Sorted by
Tagged with
1 vote
1 answer
346 views

The original Zermelo set theory explicitly allowed for urelements. What was the reason that led Zermelo to formulate the Axiom of Infinity in terms of the existence of a set of the kind that has an ...
Zuhair Al-Johar's user avatar
8 votes
0 answers
193 views

Consider the following theories: $T_1$: $\mathsf{ZFC+PD}$ where $\mathsf{PD}$ is stated as a schema. $T_2$: $\mathsf{ZFC+PD}$ where $\mathsf{PD}$ is a single sentence in the language of set theory. $...
n901's user avatar
  • 1,519
1 vote
1 answer
164 views

Say that a forcing notion $\mathbb{P}$ is slow iff there is some $f:\mathbb{R}\rightarrow\mathbb{R}$ (in $V$) such that for every $\mathbb{P}$-name for a real, $\nu$, we have $\Vdash_\mathbb{P}\exists ...
Noah Schweber's user avatar
13 votes
3 answers
809 views

Given AC, it is easy to see there is no function $f$ from ${\cal P}X$ to $X$ for an infinite set $X$ such that $f(A)\ne f(B)$ for incomparable $A$ and $B$ (i.e., $A\not\subseteq B$ and $B\not\subseteq ...
Alexander Pruss's user avatar
15 votes
1 answer
442 views

Below work in $\mathsf{ZFC+CH}$ for simplicity. Say that a (set) forcing notion $\mathbb{P}$ captures a map $f:\mathbb{R}\rightarrow\mathbb{R}$ iff there is some $\mathbb{P}$-name for a real $\nu$ ...
Noah Schweber's user avatar
12 votes
1 answer
1k views

The counting measure on $\mathbb{R}^n$ is a map that takes a subset $A$ of $\mathbb{R}^n$ and returns its cardinality if it is finite or the symbol $\infty$ if it is infinite. So, if $A\subseteq\...
Cosine's user avatar
  • 1,118
2 votes
1 answer
219 views

Let ${}^\omega\omega$ denote the set of functions $f:\omega\to \omega$. For $f, g \in {}^\omega\omega$ we define $f\leq^* g$ if there is $N\in\omega$ such that $f(n)\leq g(n)$ for all $n\in \omega$ ...
Dominic van der Zypen's user avatar
6 votes
1 answer
348 views

For $n\in\omega$ and $x$ a real let $C_n^x$ be the canonical $\Pi^1_n(x)$-complete set. E.g. $C_1^x=\mathcal{O}^x$, etc. I recall seeing long ago the fact that, assuming large cardinals (precisely: ...
Noah Schweber's user avatar
5 votes
0 answers
134 views

It's well known (and not so hard to prove directly) that for any topological space $X$ the group $C^b(X, \mathbb Z)$ — locally constant functions taking only finitely many values — is a free abelian ...
Denis T's user avatar
  • 6,000
1 vote
0 answers
170 views

I am reading Kunen's books on set theory and logic. In his approach, the metatheory is finitistic (which can be approximated in PRA). This implies that in the finitistic metatheory, one can do formal ...
Link L's user avatar
  • 235
16 votes
1 answer
710 views

This mathematical game occurred to me. It may be quite basic for experts, but it seems to lead to some interesting questions. Turns are indexed by elements of $\mathbb{N} = \{1,2,\ldots, \}$. In turn $...
Mark Wildon's user avatar
  • 11.9k
2 votes
0 answers
141 views

I am trying to get myself familiar with normalization of iteration trees, and one technical concept which I find especially hard to parse is inflation. I am following the notation of Farmer ...
Raczel Chowinski's user avatar
15 votes
1 answer
744 views

Working in $ZFC$, the statement "$0^\sharp$ exists" is often liberally taken to be one of many known equivalent statements. However, working in $Z_2$ or $ZFC^-$ (with collection, well-...
user116499's user avatar
8 votes
1 answer
349 views

It seems that Jensen's proof of the consistency of CH + SH used class forcing, but the revelant properties are not clearly verified. I haven't learnt about class forcing, so I wonder whether it is ...
Ning Gan's user avatar
7 votes
1 answer
294 views

For a regular cardinal $\kappa$, a $\kappa$ tree $T$ is called special when there is a regressive function $f : T \to T$ (regressive in the tree order) so that the inverse image of every point is the ...
Monroe Eskew's user avatar

15 30 50 per page
1
2 3 4 5
392