启动报错

[f754699]

Is there an existing issue for this?

• I have searched the existing issues

Describe the bug

 File "F:\pythonproject\sanicResolve2\.venv\Lib\site-packages\sanic\mixins\startup.py", line 1180, in serve
    while cls._get_process_states(worker_state):
                                  ^^^^^^^^^^^^
UnboundLocalError: cannot access local variable 'worker_state' where it is not associated with a value

Code snippet

from sanic import Sanic, text, json

app = Sanic("fuwu")

if __name__ == '__main__':
    app.run(host="0,0,0,0", port=8000, )

Expected Behavior

启动就报错，

How do you run Sanic?

as a model

Operating System

Windows

Sanic Version

sanic = {extras = ["ext"], version = "^24.6.0"}

Additional context

No response

[ChihweiLHBird]

from sanic import Sanic, text, json

app = Sanic("fuwu")

if __name__ == '__main__':
    app.run(host="0.0.0.0", port=8000)

Setting the correct host name seems to address the issue. But we might want to implement a host name validator to avoid confusing error message.

把host里的,改为.即可解决问题。同时建议在Linux或Unix系统上尝试

I am looking into it, the previous message above was incorrect.

[pygeek]

This is still a bug, however. mixins.startup.serve should still exit gracefully—fixed in my PR.