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April 10, 2009 at 9:47 am #24552
saiful
Memberthis is my pic.php
i want to load image into mysql database table how pls any one help me<?php
include_once(‘config.php’);//define a maxim size for the uploaded images in Kb
define ("MAX_SIZE","100");//This function reads the extension of the file. It is used to determine if the file is an image by checking the extension.
function getExtension($str) {
$i = strrpos($str,".");
if (!$i) { return ""; }
$l = strlen($str) – $i;
$ext = substr($str,$i+1,$l);
return $ext;
}//This variable is used as a flag. The value is initialized with 0 (meaning no error found)
//and it will be changed to 1 if an errro occures.
//If the error occures the file will not be uploaded.
$errors=0;
//checks if the form has been submitted
if(isset($_POST))
{
//reads the name of the file the user submitted for uploading
$image=$_FILES;
//if it is not empty
if ($image)
{
//get the original name of the file from the clients machine
$filename = stripslashes($_FILES);
//get the extension of the file in a lower case format
$extension = getExtension($filename);
$extension = strtolower($extension);
//if it is not a known extension, we will suppose it is an error and will not upload the file,
//otherwise we will do more tests
if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif"))
{
//print error message
echo ‘<h1>Unknown extension!</h1>’;
$errors=1;
}
else
{
//get the size of the image in bytes
//$_FILES is the temporary filename of the file
//in which the uploaded file was stored on the server
$size=filesize($_FILES);//compare the size with the maxim size we defined and print error if bigger
if ($size > MAX_SIZE*1024)
{
echo ‘<h1>You have exceeded the size limit!</h1>’;
$errors=1;
}//we will give an unique name, for example the time in unix time format
$image_name=time().’.’.$extension;
//the new name will be containing the full path where will be stored (images folder)
$newname="images/".$image_name;
//we verify if the image has been uploaded, and print error instead
$copied = copy($_FILES, $newname);
if (!$copied)
{
echo ‘<h1>Copy unsuccessfull!</h1>’;
$errors=1;
}}}}//If no errors registred, print the success message
if(isset($_POST) && !$errors)
{
echo "<h1>File Uploaded Successfully</h1>";
}?>
<!–next comes the form, you must set the enctype to "multipart/frm-data" and use an input type "file" –>
<form name="newad" method="post" enctype="multipart/form-data" action="show.php">
<table>
<tr><td><input type="file" name="image"></td></tr>
<tr><td><input name="Submit" type="submit" value="Upload image"></td></tr>
</table>
</form>April 28, 2009 at 12:37 pm #56856akeenlabs
ParticipantI’m confused. The code you posted is correct and will successfully upload an image (I tried it myself).
Are you asking how to modify the sample code to put the file in a database instead of the images folder? If so, my response is you shouldn’t; you should never store an image in a database.
Are you asking how to store the path to the image in the database?
Please clarify.
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