Java Program to Find Transpose of a Matrix
In this program, you’ll learn to find and print the transpose of a given matrix in Java.
Transpose of a matrix is the process of swapping the rows to columns. For 2x3 matrix,
Matrix a11 a12 a13 a21 a22 a23 Transposed Matrix a11 a21 a12 a22 a13 a23
Example: Program to Find Transpose of a Matrix
public class Transpose {public static void main(String[] args) {int row = 2, column = 3;int[][] matrix = { {2, 3, 4}, {5, 6, 4} };// Display current matrixdisplay(matrix);// Transpose the matrixint[][] transpose = new int[column][row];for(int i = 0; i < row; i++) {for (int j = 0; j < column; j++) {transpose[j][i] = matrix[i][j];}}// Display transposed matrixdisplay(transpose);}public static void display(int[][] matrix) {System.out.println("The matrix is: ");for(int[] row : matrix) {for (int column : row) {System.out.print(column + " ");}System.out.println();}}}
When you run the program, the output will be:
The matrix is: 2 3 4 5 6 4 The matrix is: 2 5 3 6 4 4
In the above program, display() function is only used to print the contents of a matrix to the screen.
Here, the given matrix is of form 2x3, i.e. row = 2 and column = 3.
For the transposed matrix, we change the order of transposed to 3x2, i.e. row = 3 and column = 2. So, we have transpose = int[column][row]
The transpose of the matrix is calculated by simply swapping columns to rows:
transpose[j][i] = matrix[i][j];