I tried to use DateTimeFormatter for it, but not found way. Duration.parse("") only use special format.
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How about something like stackoverflow.com/questions/6403851/…?cmbuckley– cmbuckley2014-07-08 22:33:25 +00:00Commented Jul 8, 2014 at 22:33
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The problem is I have to use java.time.Duration class, not joda time classes.roman-v1– roman-v12014-07-08 22:36:12 +00:00Commented Jul 8, 2014 at 22:36
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I found way to parse string to TemporalAccessor, may be there is a way get from it Duration?roman-v1– roman-v12014-07-08 22:48:17 +00:00Commented Jul 8, 2014 at 22:48
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Can you make use of DateTimeFormatter?cmbuckley– cmbuckley2014-07-09 08:30:06 +00:00Commented Jul 9, 2014 at 8:30
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3 Answers
You can parse the String yourself and reformat it into the format required by Duration
String value = ... //mm:ss
String[] fields = value.split(":");
return Duration.parse(String.format("PT%dM%sS", fields[0], fields[1]));
1 Comment
roman-v1
I wanted to use some of facilities of java 8, because format can be changed later, but now it fits. Thanks, dkatzel.
The accepted answer guides in the right direction but it has the following problems which may be difficult for a beginner to figure out and correct:
- It does not follow the correct format of
Durationwhich starts withPT. - It should use
%sinstead of%dforfields[0]asfields[0]is of type,String.
After correcting these two things, the return statement will become
return Duration.parse(String.format("PT%sM%sS", fields[0], fields[1]));
An alternative to splitting and formatting can be to use String#replaceAll as shown below:
import java.time.Duration;
public class Main {
public static void main(String[] args) {
// Test
System.out.println(parseToDuration("09:34"));
System.out.println(parseToDuration("90:34"));
System.out.println(parseToDuration("9:34"));
System.out.println(parseToDuration("0:34"));
System.out.println(parseToDuration("00:04"));
System.out.println(parseToDuration("1:2"));
}
static Duration parseToDuration(String value) {
return Duration.parse(value.replaceAll("(\\d{1,2}):(\\d{1,2})", "PT$1M$2S"));
}
}
Output:
PT9M34S
PT1H30M34S
PT9M34S
PT34S
PT4S
PT1M2S
The regex, (\d{1,2}):(\d{1,2}) has two capturing groups: group(1) is specified with $1 and group(2) is specified with $2 in the replacement string. Each capturing group has \d{1,2} which specifies 1 to 2 digit(s).
answered Dec 30, 2020 at 23:31
Arvind Kumar Avinash
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Comments
IMHO, java 8 doesn't provide any facility for custom duration parsing.
You should to do it "manually". For example (an efficient way) :
import static java.lang.Integer.valueOf;
import java.time.Duration;
public class DurationParser {
public static Duration parse(String input) {
int colonIndex = input.indexOf(':');
String mm = input.substring(0, colonIndex);
String ss = input.substring(colonIndex + 1);
return Duration.ofMinutes(valueOf(mm)).plusSeconds(valueOf(ss));
}
}
