Copy certain files from one folder to another using python

Question

I am trying to copy only certain files from one folder to another. The filenames are in a attribute table of a shapefile.

I am successful upto writing the filenames into a .csv file and list the column containing the list of the filenames to be transferred. I am stuck after that on how to read those filenames to copy them to another folder. I have read about using Shutil.copy/move but not sure how to use it. Any help is appreciated. Below is my script:

import arcpy
import csv
import os
import sys
import os.path
import shutil
from collections import defaultdict
fc = 'C:\\work_Data\\Export_Output.shp'
CSVFile = 'C:\\wokk_Data\\Export_Output.csv'
src = 'C:\\UC_Training_Areas'
dst = 'C:\\MOSAIC_Files'

fields = [f.name for f in arcpy.ListFields(fc)]
if f.type <> 'Geometry':
    for i,f in enumerate(fields):

        if f in (['FID', "Area", 'Category', 'SHAPE_Area']):
            fields.remove (f)    

with open(CSVFile, 'w') as f:
f.write(','.join(fields)+'\n') 
with arcpy.da.SearchCursor(fc, fields) as cursor:
    for row in cursor:
        f.write(','.join([str(r) for r in row])+'\n')

f.close()


columns = defaultdict(list) 
with open(CSVFile) as f:
  reader = csv.DictReader(f) 
  for row in reader: 
      for (k,v) in row.items(): 
         columns[k].append(v) 


print(columns['label'])

You may want to edit your code so that it is runnable via copy/paste. The indentation, etc... is off right now. Additionally, when you use the with(open(filename, 'w') as f:.... idiom, you do not need to use a f.close(). When you exit the with block the file will be closed automatically.. Finally, a question ... in this example is the text printed in the final line print(columns['label']) the name of the file that you want to copy to your destination directory ? Otherwise, I'm curious — OYRM
– OYRM, Commented Apr 27, 2015 at 1:29

OYRM · Accepted Answer · 2015-04-27 01:39:55Z

3

Given the name of the file columns['label'] you can use the following to move a file

srcpath = os.path.join(src, columns['label'])
dstpath = os.path.join(dst, columns['label'])
shutil.copyfile(srcpath, dstpath)

answered Apr 27, 2015 at 1:39

OYRM

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Adreeta Sarmah · Accepted Answer · 2015-05-27 00:49:43Z

2

Here is the script I used to solve my problem:

import os
import arcpy
import os.path
import shutil
featureclass = "C:\\work_Data\\Export_Output.shp"
src = "C:\\Data\\UC_Training_Areas"
dst = "C:\\Data\\Script"

rows = arcpy.SearchCursor(featureclass)
row = rows.next()
while row:
     print row.Label
     shutil.move(os.path.join(src,str(row.Label)),dst)
     row = rows.next()

answered May 27, 2015 at 0:49

Adreeta Sarmah

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Ukeme N · Accepted Answer · 2017-05-30 02:11:48Z

1

Think of it this ways way source and destination assuming you want to copy file from your picture folder to your image folder located somewhere in your machine destination
X is your machine name Z is the file name``

import os;
import shutil;
import glob;

source="C:/Users/X/Pictures/test/Z.jpg"
dest="C:/Users/Public/Image"

    if os.path.exists(dest):
    print("this folder exit in this dir")
else:
    dir = os.mkdir(dest)

for file in glob._iglob(os.path.join(source),""):
    shutil.copy(file,dest)
    print("done")

answered May 30, 2017 at 2:11

Ukeme N

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