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Ruby | Integer upto() function

Last Updated : 12 Jul, 2025
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The upto function in Ruby returns all the numbers from a given to number itself. It iterates the given block, passing in increasing values from number1 up to number2. If no block is given, an Enumerator is returned instead.

Syntax: (number1).upto(number2)

Parameter: The function takes number1 and number2 which is the range in which the numbers are returned. It also takes a block. 

Return Value: The function returns all the numbers from number1 to number2 itself.


Example 1: 

Ruby 
#Ruby program for upto() function

#Initializing the number
num1 = 8 num2 = 12

#Prints the number from num1 to num2
                puts num1.upto(num2)
{
    | i | print i, " "
}

#Initializing the number
num3 = 5 num4 = 15

#Prints the number from num3 to num4
                puts num3.upto(num4)
{
    | i | print i, " "
}

Output: 

8 9 10 11 12 8
5 6 7 8 9 10 11 12 13 14 15 5


Example 2: 

Ruby 
#Ruby program for upto() function

#Initializing the number
num1 = 1 num2 = 3

#Prints the number from num1 to num2
                puts num1.upto(num2)
{
    | i | print i, " "
}

#Initializing the number
num3 = -7 num4 = -2

#Prints the number from num3 to num4
                  puts num3.upto(num4)
{
    | i | print i, " "
}

Output: 

1 2 3 1
-7 -6 -5 -4 -3 -2 -7


Example 3: 

Ruby 
#Ruby program for upto() function

#Initializing the number
num1 = 1 num2 = 3

#Returns an enumerator
#since no block is passed
                puts num1.upto(num2)

Output: 

#


Reference: https://devdocs.io/ruby~2.5/integer#method-i-upto
 


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