C Program to Input 2 Binary Strings and Print their Binary Sum

This C Program takes an input to 2 binary strings and print their binary sum.

Here is a source code of the C program to input 2 binary strings and print their binary sum. The C program is successfully compiled and run on a Linux system. The program output is also shown below.

```
/*
```

 * C Program to Input 2 Binary Strings and Print their Binary

```
 * Sum 
```
```
 */
```
```
#include <stdio.h>
```
```
#include <string.h>
```
```
#include <stdlib.h>
```
```
 
```
```
int bin_verify(char []);
```
```
void sum(char [], char [], char []);
```
```
 
```
```
int main()
```
```
{
```

    char bin1[33], bin2[33], result[33];

```
    int len1, len2, check;
```
```
 
```
```
    printf("Enter binary number 1: ");
```
```
    scanf("%s", bin1);
```
```
    printf("Enter binary number 2: ");
```
```
    scanf("%s", bin2);
```
```
    check = bin_verify(bin1);
```
```
    if (check)
```
```
    {
```

        printf("Invalid binary number %s.\n", bin1);

```
        exit(0);
```
```
    }
```
```
    check = bin_verify(bin2);
```
```
    if (check)
```
```
    {
```

        printf("Invalid binary number %s.\n", bin2);

```
        exit(0);
```
```
    }
```
```
    sum(bin1, bin2, result);
```

    printf("%s + %s = %s\n", bin1, bin2, result);

```
 
```
```
    return 0;
```
```
}
```
```
 
```
```
int bin_verify(char str[])
```
```
{
```
```
    int i;
```
```
 
```
```
    for (i = 0; i < strlen(str); i++)
```
```
    {
```

        if ((str[i] - '0' != 1 ) && (str[i] - '0' != 0))

```
        {
```
```
            return 1;
```
```
        }
```
```
    }
```
```
 
```
```
    return 0;
```
```
}
```
```
 
```

void sum(char bin1[], char bin2[], char result[])

```
{
```
```
    int i = strlen(bin1) - 1;
```
```
    int j = strlen(bin2) - 1;
```
```
    int carry = 0, temp, num1, num2;
```
```
 
```
```
    while (i > -1 && j > -1)
```
```
    {
```
```
        num1 = bin1[i] - '0';
```
```
        num2 = bin2[j] - '0';
```
```
        temp = num1 + num2 + carry;
```
```
        if (temp / 2 == 1)
```
```
        {
```
```
            carry = 1;
```
```
            temp %= 2;
```
```
        }
```
```
        if (i > j)
```
```
        {
```
```
            result[i + 1] = temp + '0';
```

            result[strlen(bin1) + 1] = '\0';

```
        }
```
```
        else
```
```
        {
```
```
            result[j +1] = temp + '0';
```

            result[strlen(bin2) + 1] = '\0';

```
        }
```
```
        i--;
```
```
        j--;
```
```
    }
```
```
    while (i > -1)
```
```
    {
```
```
        temp = bin1[i] + carry - '0';
```
```
        if (temp / 2 == 1)
```
```
        {
```
```
            carry = 1;
```
```
            temp %= 2;
```
```
        }
```
```
        result[i + 1] = temp + '0';
```
```
        i--;
```
```
    }
```
```
    while (j > -1)
```
```
    {
```
```
        temp = bin2[j] + carry - '0';
```
```
        if (temp / 2 == 1)
```
```
        {
```
```
            carry = 1;
```
```
            temp %= 2;
```
```
        }
```
```
        result[j + 1] = temp + '0';
```
```
        j--;
```
```
    }
```
```
    if (carry)
```
```
    {
```
```
        result[0] = '1';
```
```
    }
```
```
    else
```
```
    {
```
```
        result[0] = '0';
```
```
    }
```
```
}
```

$ gcc binarynum.c
$ ./a.out
Enter binary number 1: 0110 
Enter binary number 2: 1011
0110 + 1011 = 10001

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