Java Program to Find Minimum Element in an Array using Binary Search

This is a Java Program to find minimum element of a rotated sorted array. The following program uses a binary search approach to find the minimum element of a rotated sorted array. Time complexity is O (log n)

Here is the source code of the Java program to find minimum element of a rotated sorted array. The Java program is successfully compiled and run on a Windows system. The program output is also shown below.

```
/*
```

 * Java Program to Find the Minimum element of a rotated

 * sorted Array using Binary Search approach

```
 */
```
```
 
```
```
import java.util.Scanner;
```
```
 
```

public class MinimumElementInRotatedSortedArray

```
{
```

    public static void main(String[] args)

```
    {
```

        Scanner scan = new Scanner(System.in);

        System.out.println("Enter number of elements in array");

```
        int N = scan.nextInt();
```
```
        int[] arr = new int[ N ];
```
```
        /* Accept N elements */
```

        System.out.println("Enter "+ N +" elements of rotated sorted array");

```
        for (int i = 0; i < N; i++)
```
```
            arr[i] = scan.nextInt();
```

        System.out.println("Minimum element = "+ min(arr));

```
    }
```
```
    public static int min(int[] arr)
```
```
    {
```

        return min(arr, 0, arr.length - 1);

```
    }
```

    public static int min(int[] arr, int low, int high)

```
    {
```
```
        if (high < low)  
```
```
            return arr[0];        
```
```
        if (high == low) 
```
```
            return arr[low];
```
```
        /* Calculate mid position */
```
```
        int mid = (high + low)/2;
```

        if (mid < high && arr[mid + 1] < arr[mid])

           return arr[mid + 1];

        if (mid > low && arr[mid] < arr[mid - 1])

```
           return arr[mid];
```
```
        /* recursively find min */   
```
```
        if (arr[high] > arr[mid])
```

           return min(arr, low, mid - 1);

```
        return min(arr, mid + 1, high);
```
```
    }
```
```
}
```

Enter number of elements in array
10
Enter 10 elements of rotated sorted array
59 78 83 99 24 29 35 49 53 56
Minimum element = 24
 
 
Enter number of elements in array
10
Enter 10 elements of rotated sorted array
14 23 34 56 61 67 75 81 90 99
Minimum element = 14
 
 
Enter number of elements in array
10
Enter 10 elements of rotated sorted array
2 3 4 5 6 7 8 9 10 1
Minimum element = 1

Sanfoundry Global Education & Learning Series – 1000 Java Programs.

If you wish to look at all Java Programming examples, go to Java Programs.

« Prev - Java Program to Implement Bellman Ford Algorithm

» Next - Java Program to Find Peak Element of an Array using Naive Method

Related Posts:

Apply for Java Internship
Check Java Books
Practice BCA MCQs
Practice Programming MCQs
Practice Information Technology MCQs

Recommended Articles: