numpy.cbrt() in Python

Last Updated : 18 Nov, 2020

This mathematical function helps user to calculate cube root of x for all x being the array elements. Syntax:

numpy.cbrt(arr, out = None, ufunc ‘cbrt’) :

Parameters :

arr  : [array_like] Input array or object
        whose elements, we need to square.

Return :

An array with cube root of x for all x i.e. array elements

Code #1 : Working

Python3

# Python program explaining
# cbrt () function
 
import numpy as np
 
arr1 = [1, 27000, 64, -1000]
print ("cbrt Value of arr1 : \n", np.cbrt(arr1))
 
arr2 = [1024 ,-128]
print ("\ncbrt Value of arr2 : ", np.cbrt(arr2))

Output :

cbrt Value of arr1 : 
 [  1.  30.   4. -10.]

cbrt Value of arr2 :  [ 10.0793684  -5.0396842]

Code #2 : Working with complex numbers

Python3

# Python program explaining
# cbrt () function
 
import numpy as np
 
a = 4 + 3j
print("cbrt(4 + 3j) : ", np.cbrt(a))
 
b = 16 + 13j
print("\ncbrt value(16 + 13j) : ", np.cbrt(b))

Output :

TypeError: ufunc 'cbrt' not supported for the input types,
and the inputs could not be safely coerced to any supported
types according to the casting rule ''safe''

Code #3 : Graphical representation

Python3

# Python program explaining
# cbrt () function
 
import numpy as np
import matplotlib.pyplot as plt
 
a = np.linspace(start = -5, stop = 150,
                num = 10, endpoint = True)
                 
print("Graphical Representation : \n", np.cbrt(a))
 
plt.title("blue : with cbrt\nred : without cbrt")
plt.plot(a, np.cbrt(a))
 
plt.scatter(a, a, color = 'red')
plt.show()

Output :

Graphical Representation : 
 [-1.70997595  2.30347441  3.08793243  3.60027433  3.99768384  4.3287262
  4.61565763  4.87076238  5.10162421  5.31329285]