OPEN
This is open, and cannot be resolved with a finite computation.
- $500
If $A\subseteq \{1,\ldots,N\}$ with $\lvert A\rvert=n$ is such that the subset sums $\sum_{a\in S}a$ are distinct for all $S\subseteq A$ then\[N \gg 2^{n}.\]
Erdős called this 'perhaps my first serious problem' (in
[Er98] he dates it to 1931). The powers of $2$ show that $2^n$ would be best possible here. The trivial lower bound is $N \gg 2^{n}/n$, since all $2^n$ distinct subset sums must lie in $[0,Nn)$. Erdős and Moser
[Er56] proved\[ N\geq (\tfrac{1}{4}-o(1))\frac{2^n}{\sqrt{n}}.\](In
[Er85c] Erdős offered \$100 for any improvement of the constant $1/4$ here.)
A number of improvements of the constant have been given (see
[St23] for a history), with the current record $\sqrt{2/\pi}$ first proved in unpublished work of Elkies and Gleason. Two proofs achieving this constant are provided by Dubroff, Fox, and Xu
[DFX21], who in fact prove the exact bound $N\geq \binom{n}{\lfloor n/2\rfloor}$.
In
[Er73] and
[ErGr80] the generalisation where $A\subseteq (0,N]$ is a set of real numbers such that the subset sums all differ by at least $1$ is proposed, with the same conjectured bound. (The second proof of
[DFX21] applies also to this generalisation.) This generalisation seems to have first appeared in
[Gr71].
This problem appears in Erdős' book with Spencer
[ErSp74] in the final chapter titled 'The kitchen sink'. As Ruzsa writes in
[Ru99] "it is a rich kitchen where such things go to the sink".
The sequence of minimal $N$ for a given $n$ is
A276661 in the OEIS.
See also
[350].
This is discussed in problem C8 of Guy's collection
[Gu04].
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This page was last edited 23 January 2026.
Additional thanks to: Zach Hunter, Ralf Stephan, and Wouter van Doorn
When referring to this problem, please use the original sources of Erdős. If you wish to acknowledge this website, the recommended citation format is:
T. F. Bloom, Erdős Problem #1, https://www.erdosproblems.com/1, accessed 2026-02-13