DISPROVED
This has been solved in the negative.
Let $P(z)=\sum_{1\leq k\leq n}a_kz^k$ for some $a_k\in \mathbb{C}$ with $\lvert a_k\rvert=1$ for $1\leq k\leq n$. Does there exist a constant $c>0$ such that, for $n\geq 2$, we have\[\max_{\lvert z\rvert=1}\lvert P(z)\rvert \geq (1+c)\sqrt{n}?\]
This is Problem 4.31 in
[Ha74], in which it is described as a conjecture of Erdős and Newman.
The lower bound of $\sqrt{n}$ is trivial from Parseval's theorem. Körner
[Ko80] constructed, for all $n\geq 2$, polynomials $P(z)=\sum_{k\leq n} a_kz^k$ with $\lvert a_k\rvert=1$ for $1\leq k\leq n$ such that, for all $z$ with $\lvert z\rvert=1$,\[(c_1-o(1))\sqrt{n} \leq \lvert P(z)\rvert \leq (c_2+o(1))\sqrt{n}\]for some absolute constants $0<c_1\leq c_2$.
The answer is no (contrary to Erdős' initial guess). Kahane
[Ka80] constructed 'ultraflat' polynomials $P(z)=\sum a_kz^k$ with $\lvert a_k\rvert=1$ such that\[P(z)=(1+o(1))\sqrt{n}\]uniformly for all $z\in\mathbb{C}$ with $\lvert z\rvert=1$, where the $o(1)$ term $\to 0$ as $n\to \infty$.
For more details see the paper
[BoBo09] of Bombieri and Bourgain and where Kahane's construction is improved to yield such a polynomial with\[P(z)=\sqrt{n}+O(n^{\frac{7}{18}}(\log n)^{O(1)})\]for all $z\in\mathbb{C}$ with $\lvert z\rvert=1$.
See also
[228] and
[1150].
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This page was last edited 23 January 2026.
Additional thanks to: Alfaiz, Mehtaab Sawhney, and Wouter van Doorn
When referring to this problem, please use the original sources of Erdős. If you wish to acknowledge this website, the recommended citation format is:
T. F. Bloom, Erdős Problem #230, https://www.erdosproblems.com/230, accessed 2026-02-13