Also read: Numpy.kron(): How to Calculate Kronecker Product Using Numpy?<\/a><\/em><\/strong><\/p>\n\n\n\n We shall get things started by first importing the numpy <\/em>library using the following code.<\/p>\n\n\n Thereafter, we shall explore further the nextafter( ) <\/em>function through each of the following sections.<\/p>\n\n\n\n The function relies on the primary inputs x1 & x2 as given below of which, x1 is the entity for which the next floating point value is to be found along the direction of x2. The other optional inputs that can also be used within the nextafter( ) <\/em>function are as follows.<\/p>\n\n\n where,<\/p>\n\n\n\n In this section let us use a couple of scalars for deploying into the nextafter( ) <\/em>function as shown below.<\/p>\n\n\n Once the above code is run, the following computation happens in the back end to return the next nearest number to \u2018a\u2019 when searched in the direction of \u2018b\u2019.<\/p>\n\n\n\n From the above explanation, it could be deduced that the direction of search is synonymous with searching a number (first input, x1) in the number line rightwards when the second input \u2018x2\u2019 is greater than the first input \u2018x1\u2019 or leftwards if the second input \u2018x2\u2019 is lesser than the first input \u2018x1\u2019.<\/p>\n\n\n\n The same logic holds good even if one uses positive or negative infinity as \u2018x2\u2019 rather than the other numbers and we shall use the following code to establish this conundrum.<\/p>\n\n\n The above result bears evidence that the nearest floating point number returned is towards the right of \u2018-10\u2019 in the number line since the direction of the search is positive infinity.<\/p>\n\n\n\n When deployed on arrays the results would be rounded off to the same number of digits after the decimal given in the array, rather than the whole 14 digits as depicted below.<\/p>\n\n\n Now that we have reached the end of this article, hope it has elaborated on how to use the\u00a0nextafter( )\u00a0<\/em>function from the\u00a0numpy\u00a0<\/em>library. Here\u2019s another article that details the calculation of the Kronecker product using numpy kron()<\/a>. There are numerous other enjoyable and equally informative articles in AskPython<\/a> that might be of great help to those who are looking to level up in Python.\u00a0Mazel tov<\/em>!<\/p>\n","protected":false},"excerpt":{"rendered":" Looking for a function to return the next floating point value of a given number in the direction of another number? Do you want the same function to carry out the same with a collection of numbers rather than a single number? Well, look no further for the numpy library has got just the thing […]<\/p>\n","protected":false},"author":44,"featured_media":38969,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[93],"tags":[],"class_list":["post-38968","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-numpy"],"blocksy_meta":[],"_links":{"self":[{"href":"https:\/\/www.askpython.com\/wp-json\/wp\/v2\/posts\/38968","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.askpython.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.askpython.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.askpython.com\/wp-json\/wp\/v2\/users\/44"}],"replies":[{"embeddable":true,"href":"https:\/\/www.askpython.com\/wp-json\/wp\/v2\/comments?post=38968"}],"version-history":[{"count":0,"href":"https:\/\/www.askpython.com\/wp-json\/wp\/v2\/posts\/38968\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.askpython.com\/wp-json\/wp\/v2\/media\/38969"}],"wp:attachment":[{"href":"https:\/\/www.askpython.com\/wp-json\/wp\/v2\/media?parent=38968"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.askpython.com\/wp-json\/wp\/v2\/categories?post=38968"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.askpython.com\/wp-json\/wp\/v2\/tags?post=38968"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}\nimport numpy as np\n<\/pre><\/div>\n\n\n
\n
\n\n\n\nSyntax of\u00a0the nextafter( )<\/em>\u00a0function<\/strong><\/h2>\n\n\n\n
\nnumpy.nextafter(x1, x2, out=None, *, where=True, dtype=None)\n<\/pre><\/div>\n\n\n
\n
\n\n\n\nUsing nextafter( )<\/em> on Scalars<\/strong><\/h2>\n\n\n\n
\na = 100\nb = -50\nnp.nextafter(a, b)\n<\/pre><\/div>\n\n\n
\n
![\"Using](\"https:\/\/www.askpython.com\/wp-content\/uploads\/2022\/12\/Using-nextafter-on-Scalars.jpg\")
\nc = -10\nd = +np.inf\nnp.nextafter(c, d)\n<\/pre><\/div>\n\n\n
![\"Using](\"https:\/\/www.askpython.com\/wp-content\/uploads\/2022\/12\/Using-nextafter-on-Scalars-in-Direction-of-Infinity.jpg\")
\n\n\n\nUsing nextafter( ) <\/em>on N-Dimensional Arrays<\/strong><\/h2>\n\n\n\n
\nar1 = np.array([[1.05, 3, 7],\n [2.9, 9, 4.3666667]])\nar2 = np.array([[-1, 0.3, +np.inf],\n [0, -np.inf, 10]])\nnp.nextafter(ar1, ar2)\n<\/pre><\/div>\n\n\n
![\"Using](\"https:\/\/www.askpython.com\/wp-content\/uploads\/2022\/12\/Using-nextafter-on-Arrays.jpg\")
\n\n\n\nConclusion<\/strong><\/h2>\n\n\n\n