feat: delete data from all index

[dl239]

• What kind of change does this PR introduce? (Bug fix, feature, docs update, ...)

• What is the current behavior? (You can also link to an open issue here)

• What is the new behavior (if this is a feature change)?

[codecov]

Codecov Report

All modified and coverable lines are covered by tests ✅

Comparison is base (b8318b8) 40.09% compared to head (32c7f54) 40.09%.

Additional details and impacted files

@@            Coverage Diff            @@
##               main    #3693   +/-   ##
=========================================
  Coverage     40.09%   40.09%           
  Complexity      657      657           
=========================================
  Files           193      193           
  Lines         11414    11414           
  Branches       1374     1374           
=========================================
  Hits           4576     4576           
  Misses         6535     6535           
  Partials        303      303           

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[github-actions]

SDK Test Report

101 files  ±0  101 suites  ±0   2m 9s ⏱️ +2s
344 tests ±0  330 ✅ ±0  14 💤 ±0  0 ❌ ±0 
469 runs  ±0  455 ✅ ±0  14 💤 ±0  0 ❌ ±0 

Results for commit 32c7f54. ± Comparison against base commit b8318b8.

This pull request removes 30 and adds 9 tests. Note that renamed tests count towards both.

  PARTITION BY db1.t1.col2 ORDER BY db1.t1.col1
  PARTITION BY t1.col2 ORDER BY t1.col1
  ROWS_RANGE BETWEEN 3 PRECEDING AND CURRENT ROW
 ) limit 10;](1)
 ) limit 10;](2)
 ) limit 10;](3)
 FROM db1.t1
 FROM t1
 WINDOW w1 AS (
 last join db2.t2 order by db2.t2.col1
…

com._4paradigm.hybridse.sdk.SqlEngineTest ‑ sqlLastJoinWithMultipleDB[,  SELECT sum(db1.t1.col1) over w1 as sum_t1_col1, db2.t2.str1 as t2_str1
 FROM db1.t1
 last join db2.t2 order by db2.t2.col1
 on db1.t1.col1 = db2.t2.col1 and db1.t1.col2 = db2.t2.col0
 WINDOW w1 AS (
  PARTITION BY db1.t1.col2 ORDER BY db1.t1.col1
  ROWS_RANGE BETWEEN 3 PRECEDING AND CURRENT ROW
 ) limit 10;](2)
com._4paradigm.hybridse.sdk.SqlEngineTest ‑ sqlLastJoinWithMultipleDB[db1,  SELECT sum(t1.col1) over w1 as sum_t1_col1, db2.t2.str1 as t2_str1
 FROM t1
 last join db2.t2 order by db2.t2.col1
 on t1.col1 = db2.t2.col1 and t1.col2 = db2.t2.col0
 WINDOW w1 AS (
  PARTITION BY t1.col2 ORDER BY t1.col1
  ROWS_RANGE BETWEEN 3 PRECEDING AND CURRENT ROW
 ) limit 10;](1)
com._4paradigm.hybridse.sdk.SqlEngineTest ‑ sqlLastJoinWithMultipleDB[null,  SELECT sum(db1.t1.col1) over w1 as sum_t1_col1, db2.t2.str1 as t2_str1
 FROM db1.t1
 last join db2.t2 order by db2.t2.col1
 on db1.t1.col1 = db2.t2.col1 and db1.t1.col2 = db2.t2.col0
 WINDOW w1 AS (
  PARTITION BY db1.t1.col2 ORDER BY db1.t1.col1
  ROWS_RANGE BETWEEN 3 PRECEDING AND CURRENT ROW
 ) limit 10;](3)
com._4paradigm.hybridse.sdk.SqlEngineTest ‑ sqlMultipleDBErrorTest[, SELECT db2.t2.str1 as t2_str1
 FROM t1
 last join db2.t2 order by db2.t2.col1
 on t1.col1 = db2.t2.col1 and t1.col2 = db2.t2.col0;
, SQL parse error: Fail to transform data provider op: table t1 not exists in database []](4)
com._4paradigm.hybridse.sdk.SqlEngineTest ‑ sqlMultipleDBErrorTest[db1, SELECT db1.t2.str1 as t2_str1
 FROM t1
 last join db2.t2 order by db2.t2.col1
 on t1.col1 = db2.t2.col1 and t1.col2 = db2.t2.col0;
, SQL parse error: Column Not found: db1.t2.str1](2)
com._4paradigm.hybridse.sdk.SqlEngineTest ‑ sqlMultipleDBErrorTest[db1, SELECT db2.t2.str1 as t2_str1
 FROM t1
 last join db2.t2 order by db2.t2.col1
 on t1.col1 = t2.col1 and t1.col2 = db2.t2.col0;
, SQL parse error: Column Not found: .t2.col1](3)
com._4paradigm.hybridse.sdk.SqlEngineTest ‑ sqlMultipleDBErrorTest[db1, SELECT t2.str1 as t2_str1
 FROM t1
 last join db2.t2 order by db2.t2.col1
 on t1.col1 = db2.t2.col1 and t1.col2 = db2.t2.col0;
, SQL parse error: Column Not found: .t2.str1](1)
com._4paradigm.hybridse.sdk.SqlEngineTest ‑ sqlMultipleDBErrorTest[null, SELECT db2.t2.str1 as t2_str1
 FROM t1
 last join db2.t2 order by db2.t2.col1
 on t1.col1 = db2.t2.col1 and t1.col2 = db2.t2.col0;
, SQL parse error: Fail to transform data provider op: table t1 not exists in database []](5)
com._4paradigm.hybridse.sdk.SqlEngineTest ‑ sqlWindowLastJoin[ SELECT sum(t1.col1) over w1 as sum_t1_col1, t2.str1 as t2_str1
 FROM t1
 last join t2 order by t2.col1
 on t1.col1 = t2.col1 and t1.col2 = t2.col0
 WINDOW w1 AS (
  PARTITION BY t1.col2 ORDER BY t1.col1
  ROWS_RANGE BETWEEN 3 PRECEDING AND CURRENT ROW
 ) limit 10;](1)

[github-actions]

Linux Test Report

    57 files  ±0     244 suites  ±0   1h 16m 24s ⏱️ +27s
12 580 tests +3  12 573 ✅ +3  7 💤 ±0  0 ❌ ±0 
17 837 runs  +3  17 830 ✅ +3  7 💤 ±0  0 ❌ ±0 

Results for commit 32c7f54. ± Comparison against base commit b8318b8.

This pull request removes 1 and adds 4 tests. Note that renamed tests count towards both.

SQLClusterDDLTest ‑ TestDelete

DBSDK/DBSDKTest ‑ DeletetMulIndex/0
DBSDK/DBSDKTest ‑ DeletetMulIndex/1
DBSDK/DBSDKTest ‑ TestDelete/0
DBSDK/DBSDKTest ‑ TestDelete/1

[tobegit3hub]

LGTM