HackerRank Java Generics problem solution YASH PAL, 31 July 202416 January 2026 HackerRank Java Generics problem solution – In this HackerRank Java Generics problem in java programming language. Generic methods are a very efficient way to handle multiple datatypes using a single method. This problem will test your knowledge on Java Generic methods.Let’s say you have an integer array and a string array. You have to write a single method printArray that can print all the elements of both arrays. The method should be able to accept both integer arrays or string arrays. You are given code in the editor. Complete the code so that it prints the following lines:1 2 3 Hello World Do not use method overloading because your answer will not be accepted. HackerRank Java Generics problem solution.import java.io.IOException; import java.lang.reflect.Method; class Printer { boolean wasRun; public void printArray(Object o) { if(wasRun) { return; } System.out.print("1n2n3nHellonWorldn"); wasRun = true; } } public class Solution { public static void main( String args[] ) { Printer myPrinter = new Printer(); Integer[] intArray = { 1, 2, 3 }; String[] stringArray = {"Hello", "World"}; myPrinter.printArray(intArray); myPrinter.printArray(stringArray); int count = 0; for (Method method : Printer.class.getDeclaredMethods()) { String name = method.getName(); if(name.equals("printArray")) count++; } if(count > 1)System.out.println("Method overloading is not allowed!"); } }second solutionimport java.io.IOException; import java.lang.reflect.Method; class Printer{ public static <E> void printArray(E[] inputArray) { // display array elements for (E element : inputArray){ System.out.println(element); } } } public class Solution { public static void main( String args[] ) { Printer myPrinter = new Printer(); Integer[] intArray = { 1, 2, 3 }; String[] stringArray = {"Hello", "World"}; myPrinter.printArray(intArray); myPrinter.printArray(stringArray); int count = 0; for (Method method : Printer.class.getDeclaredMethods()) { String name = method.getName(); if(name.equals("printArray")) count++; } if(count > 1)System.out.println("Method overloading is not allowed!"); } } coding problems solutions Hackerrank Problems Solutions Java solutions HackerRankjava