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Sunday, October 15th, 2017 04:07 pm
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For any and all real epsilon greater than zero, there exists a real delta greater than zero, such that for any real x within the open interval (a minus delta, a plus delta), the function f(x) will always exist within an epsilon-interval of the limit L, i.e. (L minus epsilon, L plus epsilon).

More simply put,
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where x-naught is a.