Java Long class

Java Math.floor() method

Last Updated : 17 Mar 2025

The java.lang.Math.floor() is used to find the largest integer value which is less than or equal to the argument and is equal to the mathematical integer of a double value.

Syntax

Parameter

Return

This method returns largest floating-point value that is less than or equal 
to the argument and is equal to a mathematical integer of a double value.

If the argument is positive or negative double value, this method will return the Floor value.
If the argument is NaN, this method will return same argument.
If the argument is Infinity, this method will return Infinity with same sign as the argument.

Example 1

public class FloorExample1
{
    public static void main(String[] args) 
    {
        double x = 94.69;
        // Input positive value, Output floor value of x
        System.out.println(Math.floor(x));
    }
}

Output:

94.0

Example 2

public class FloorExample2
{
    public static void main(String[] args) 
    {
        double x = -39.28;
        // Input negative value, Output floor value of x
        System.out.println(Math.floor(x));
    }
}

Output:

-40.0

Example 3

public class FloorExample3
{
    public static void main(String[] args) 
    {
        double x = 0.0;
        // Input positive zero, Output positive zero 
        System.out.println(Math.floor(x));
    }
}

Output:

0.0

Example 4

public class FloorExample4
{
    public static void main(String[] args) 
    {
        double x = -7.0 / 0;
        // Input negative infinity, Output negative infinity
        System.out.println(Math.floor(x));
    }
}

Output:

-Infinity

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Java Math.floor() method

Syntax

Parameter

Return

Example 1

Example 2

Example 3

Example 4

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Java Math.floor() method

Syntax

Parameter

Return

Example 1

Example 2

Example 3

Example 4

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