Let's simulate some simple examples, to clarify what you may want to do.
Let's start with a bimodal sample, which would look like this:

It is definitively bimodal, but would you say your device worked well? Maybe not, because the densities around 0 are still quite high (in many instances, it either did not "push" the result at all, or not much).
Now, let's look at another bimodal distribution;

I think we could agree that your device worked much better this time (much fewer observatiosn at or around 0).
And let's look at a 3rd example

I think we can agree that your device now works "perfectly".
But...
- All 3 are bimodal (and I do not think that declaring one "more bimodal" than the other is sensible)
- In all 3 cases, the mean is 0, and the median is 0 (the variances are different, but that will not lead us any place useful), and so no t-test, or median test, etc. will let you discern a difference.
So it is not a t-test (for means), or a median test, or a test of multi-modality that you need. Instead it is a test looking at what proportions of your observations are within a range $[-\epsilon, +\epsilon]$, with epsilon of your choosing (in your context, how far from 0 must the object be for you to say it is meaningfully far from 0).
And you also need to define another parameter $p$, which is the proportion of observations in the $[-\epsilon, +\epsilon]$ interval (aka "0 interval") which, in your context, you would consider meaningless (in other words, you would be satisfied with the performance of your device, even if such a small proportion was in the "0 interval".
Then the test you can use is a binomial test. You said that you can "easily" collect 1000 datapoints, so the (relative) low power of a binomial test is no longer an issue.
Then dichotomize your observations; inside the "0 interval", or outside. And compute the upper bound of the CI of the proportion observed in the "0 interval". If it is below $p$, you have demonstrated, at the selected significance level, that your device would allow, at most $100.p\%$ of the results in the "0 interval", and so 'gets the job done'.
Yes, dichotomizing a continuous variable is (usually appropriately) frowned upon; but you can collect large enough samples so that the objections do not matter in practice. And all the continuous proportion tests I know of are based on normal approximations, or normal assumptions, but a bimodal distribution is anything but normal...