Java Long class

Java Byte compareTo() method

Last Updated : 17 Mar 2025

The compareTo() method of Java Byte class compares two Byte objects numerically

Syntax:

Parameters:

The parameter 'anotherByte' represents the Byte to be compared.

Specified by

This method is specified by compareTo in interface Comparable<Byte>

Return Value

This method returns an integer value.

It returns zero, if this Byte is equal to the parameter.
It returns positive one, if this Byte is numerically greater than the argument Byte.
It returns negative one, if this Byte is numerically smaller than the argument Byte.

Example 1

Example

public class Main {
    public static void main(String[] args) {
        Byte byte1=127;
        Byte byte2=67;
        //It compares two Byte objects numerically
        int val=byte1.compareTo(byte2);
        if(val==0){
            System.out.println(byte1+" and "+byte2+" values are equal.");
        }
        else if(val>0){
            System.out.println(byte1+" is greater than "+byte2+" .");
        }
        else{
            System.out.println(byte2+" is greater than "+byte1+" .");
        }
    }
}

Compile and Run

Output:

127 is greater than 67 .

Example 2

import java.util.Scanner;
public class JavaByteCompareToExample2 {
    public static void main(String[] args) {
        Byte byte1=18;
        Scanner scanner=new Scanner(System.in);
        System.out.print("Enter your age : ");
        byte byte2=scanner.nextByte();
        int val=byte1.compareTo(byte2);
        if (val<0){
            System.out.println("Congratulations! You are an adult. Now you can vote.");
        }
        else {
            int byte3=byte1-byte2;
            System.out.println("Oops! You are not an adult. You can vote after "+ byte3+" years.");
        }
    }
}

Output:

Enter your age : 24
Congratulations! You are an adult. Now you can vote.

Example 3

Example

public class Main {
    public static void main(String[] args) {
        //byte value should be in the range between -127 to 128
        Byte b1= 567;
        byte b2=Byte.MIN_VALUE;
        int val=b1.compareTo(b1);
        if(val>0){
            System.out.println(b1+" is greater than "+b2);
        }
        else{
            System.out.println(b2+" is greater than "+b1);
        }
    }
}

Compile and Run

Output:

Error:(5, 18) java: incompatible types: int cannot be converted to java.lang.Byte

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Java Byte compareTo() method

Syntax:

Parameters:

Specified by

Return Value

Example 1

Example

Example 2

Example 3

Example

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Java Byte compareTo() method

Syntax:

Parameters:

Specified by

Return Value

Example 1

Example

Example 2

Example 3

Example

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